Renal Clearance Calculator

Find the clearance of any substance from urine and plasma concentrations, plus filtration fraction from GFR and RPF — every step shown.

Clearance

How to calculate renal clearance

Clearance is the volume of plasma the kidneys completely clear of a substance per minute: Cx = (Ux × V) / Px, where Ux is the substance's urine concentration, V is urine flow rate, and Px is its plasma concentration. Which substance you use determines what the number means. Inulin is freely filtered but never reabsorbed or secreted, so its clearance directly equals GFR (glomerular filtration rate). PAH is filtered and almost completely secreted, so its clearance approximates RPF (renal plasma flow). The ratio GFR/RPF is the filtration fraction — normally about 20%, the share of plasma flowing through the glomerulus that actually becomes filtrate.

Normal values: GFR ≈ 125 mL/min (~180 L/day), RPF ≈ 600-700 mL/min, filtration fraction ≈ 20%.

Related tools: Osmotic pressure & tonicity · all biochem tools.

Worked example: inulin clearance (GFR) and filtration fraction

Inulin: urine concentration 125 mg/mL, flow rate 1 mL/min, plasma concentration 1 mg/mL (the tool's defaults).

Cx = (Ux × V) / Px = (125 × 1) / 1 = 125 mL/min This is a normal GFR — inulin's clearance is used as the reference standard because it's neither reabsorbed nor secreted.

With RPF measured (via PAH clearance) at 625 mL/min:

FF = GFR / RPF = 125 / 625 = 0.20 = 20% Right at the normal filtration fraction — about a fifth of the plasma flowing through the glomerulus becomes filtrate.

Practice problems

1. PAH: urine concentration 15 mg/mL, flow rate 1.2 mL/min, plasma concentration 0.03 mg/mL. Find the clearance (this estimates RPF).

Show answer
Cx = (15 × 1.2) / 0.03 = 18/0.03 = 600 mL/min A textbook-normal renal plasma flow — consistent with PAH being almost completely cleared from plasma in one pass through the kidney.

2. Creatinine: urine concentration 60 mg/mL, flow rate 1.5 mL/min, plasma concentration 1.2 mg/mL. Find the clearance. Is this GFR normal, low, or high?

Show answer
Cx = (60 × 1.5) / 1.2 = 90/1.2 = 75 mL/min 75 mL/min is well below the normal ~125 mL/min GFR — consistent with reduced kidney function (a plasma creatinine of 1.2 mg/mL is itself already a mild-to-moderate elevation above the typical ~0.6-1.0 mg/mL range).

FAQ

Why inulin for GFR specifically?
It's freely filtered but never reabsorbed or secreted, so urine output per minute exactly equals the filtered amount — a direct GFR measure. Creatinine approximates this clinically (endogenous, no infusion needed) but is slightly secreted, running measured clearance a bit above true GFR.

Why does PAH estimate renal plasma flow instead?
PAH is filtered AND actively secreted, so it's almost completely removed from plasma in one pass — its clearance approximates total plasma flow through the kidney, not just the filtered fraction.

What does filtration fraction tell you?
FF = GFR/RPF, normally ~20% — the share of renal plasma flow that actually gets filtered into the tubule, versus the ~80% that continues to the peritubular capillaries.

What does clearance above or below GFR mean?
Above GFR (like PAH) means net tubular secretion is adding to what filtration alone delivers. Below GFR means net reabsorption is occurring.